<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-3456645307742175214</id><updated>2011-04-21T17:36:22.699-07:00</updated><category term='wikiHow'/><category term='question 1'/><category term='Isaac Newton'/><category term='funny'/><category term='center'/><category term='automatic'/><category term='AP'/><category term='how to'/><category term='101'/><category term='calculus'/><category term='solutions'/><category term='gravity'/><category term='game'/><category term='part b'/><category term='Advanced Placement'/><category term='calc101.com'/><category term='free-response'/><category term='test'/><category term='jerk'/><category term='derivative'/><category term='2000'/><category term='genius'/><category term='new year'/><category term='part a'/><category term='physics'/><category term='integral'/><title type='text'>Calculus and Physics</title><subtitle type='html'>Isaac Newton's greatest creations</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>8</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-727623157943954054</id><published>2007-01-30T21:20:00.000-08:00</published><updated>2007-01-30T20:22:14.561-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='calculus'/><category scheme='http://www.blogger.com/atom/ns#' term='2000'/><category scheme='http://www.blogger.com/atom/ns#' term='question 1'/><category scheme='http://www.blogger.com/atom/ns#' term='free-response'/><category scheme='http://www.blogger.com/atom/ns#' term='AP'/><category scheme='http://www.blogger.com/atom/ns#' term='part b'/><title type='text'>2000 Calculus AB Free-Response: Question 1 Part B</title><content type='html'>&lt;p&gt;Lets continue now with Question 1 Part B.&lt;/p&gt;&lt;p&gt;Part be asks that we revolve f(x) and g(x) around the x-axis. To do this, must integrate f(x)^2 - g(x)^2 using the same parameters as Part A (0 to .94194). Then, after it is integrated, we must multiply it by pi.&lt;/p&gt;&lt;p&gt;Remember that the first part of the AP Calculus free response allows you to use a graphing calculator. A graphing calculator is actually required to solve this problem because the indefinite integral of e^(-x^2) can not be found.&lt;/p&gt;&lt;p&gt;Back to the problem... just put in the definite integral in your calculator and press enter. If you have a TI-83 Plus or TI-84 Plus, type fnInt((e^((-2x)^2)-((1-cos(x))^2),x,0,.94194).&lt;/p&gt;&lt;p&gt;You should get Volume = 1.7466 units^3&lt;br /&gt;&lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-727623157943954054?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/727623157943954054/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=727623157943954054' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/727623157943954054'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/727623157943954054'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2007/01/2000-calculus-ab-free-response-question_09.html' title='2000 Calculus AB Free-Response: Question 1 Part B'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-7159746583114282495</id><published>2007-01-19T19:01:00.000-08:00</published><updated>2007-01-21T19:47:58.260-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='jerk'/><category scheme='http://www.blogger.com/atom/ns#' term='funny'/><category scheme='http://www.blogger.com/atom/ns#' term='physics'/><title type='text'>DON'T BE A JERK!</title><content type='html'>Today, while sitting in my physics class, I saw a very funny shirt that one of my peers was wearing. You need some knowledge of physics and calculus to understand this one. Take a look below.&lt;br /&gt;&lt;a onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}" href="http://1.bp.blogspot.com/_trQTLS--T7M/RbQzlf1FpCI/AAAAAAAAAAY/cuYDp0Fn8I8/s1600-h/dont-be-a-jerk.gif"&gt;&lt;img style="cursor: pointer;" src="http://1.bp.blogspot.com/_trQTLS--T7M/RbQzlf1FpCI/AAAAAAAAAAY/cuYDp0Fn8I8/s320/dont-be-a-jerk.gif" alt="" id="BLOGGER_PHOTO_ID_5022696203717288994" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;p&gt;Still don't get it? You need to know that s is displacement. The derivative of s with respect to time,  (d^2)s/(dt^2), is acceleration. The derivative of acceleration, (d^3)s/(dt^3), is called jerk. So the shirt read "DON'T BE A &lt;span style="font-style: italic;"&gt;JERK&lt;/span&gt;."&lt;/p&gt;&lt;p&gt;Pretty funny, right?&lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-7159746583114282495?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/7159746583114282495/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=7159746583114282495' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/7159746583114282495'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/7159746583114282495'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2007/01/today-while-sitting-in-my-physics-class.html' title='DON&apos;T BE A JERK!'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://1.bp.blogspot.com/_trQTLS--T7M/RbQzlf1FpCI/AAAAAAAAAAY/cuYDp0Fn8I8/s72-c/dont-be-a-jerk.gif' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-8121516482555021605</id><published>2007-01-04T16:57:00.000-08:00</published><updated>2007-01-04T17:22:51.222-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='calculus'/><category scheme='http://www.blogger.com/atom/ns#' term='2000'/><category scheme='http://www.blogger.com/atom/ns#' term='question 1'/><category scheme='http://www.blogger.com/atom/ns#' term='part a'/><category scheme='http://www.blogger.com/atom/ns#' term='free-response'/><category scheme='http://www.blogger.com/atom/ns#' term='AP'/><category scheme='http://www.blogger.com/atom/ns#' term='solutions'/><category scheme='http://www.blogger.com/atom/ns#' term='Advanced Placement'/><title type='text'>2000 Calculus AB Free-Response: Question 1 Part A</title><content type='html'>&lt;p&gt;In my last post, &lt;a href="http://calculusphysics.blogspot.com/2007/01/learn-from-past-ap-tests-2000.html"&gt;Learn from the past AP Tests: 2000&lt;/a&gt;, I linked to the 2000 AP Calculus AB Free-Response questions. Today, I will start to go through the solutions, starting with question number one, part A.&lt;/p&gt;&lt;p&gt;Question number one, part A asks for the area of a region, R, between two functions (also known as curves),  which I will call f(x) and g(x). f(x)=e^(-(x^2)) and g(x)=1 - cos(x)&lt;/p&gt;&lt;p&gt;To solve, we must first find the area under the top curve, f(x). To do this, we must integrate f(x) (Also known as taking the antiderivative. The antiderivative of f(x) can be written as F(x).). So F(x)= -(1/2)e^(-(x^2)). The easiest way to do that is u substitution.&lt;br /&gt;&lt;/p&gt;&lt;p&gt;Now, lets integrate g(x). G(x)= x - sin(x).&lt;br /&gt;&lt;/p&gt;&lt;p&gt;Now that we know the two antiderivatives, we need to find out wher f(x) intersect with g(x); so where f(x) = g(x). Remember, this is a calculator portion, so you can simply plug this into a calculator (In fact, you can solve this question in a much easier manner using your calculator. I will show you how in my next post.). The results show the intersection, B, is at .94194.&lt;/p&gt;&lt;p&gt;Lets plug it all in! The integral of f(x) - g(x) from A=0 to B=.94194, can also be written as [F(x) - G(x)]&lt;sub&gt;0&lt;/sub&gt; &lt;sup&gt;.94194&lt;/sup&gt;, which can be written as F(.94194)-F(0) - (G(.94194) - G(0)).&lt;/p&gt;&lt;p&gt;It all equals .591.&lt;/p&gt;&lt;p&gt;If you have any questions, please leave a comment.&lt;br /&gt;&lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-8121516482555021605?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/8121516482555021605/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=8121516482555021605' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/8121516482555021605'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/8121516482555021605'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2007/01/2000-calculus-ab-free-response-question.html' title='2000 Calculus AB Free-Response: Question 1 Part A'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-6875198845507059149</id><published>2007-01-03T10:22:00.000-08:00</published><updated>2007-01-03T10:37:18.823-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='calculus'/><category scheme='http://www.blogger.com/atom/ns#' term='2000'/><category scheme='http://www.blogger.com/atom/ns#' term='free-response'/><category scheme='http://www.blogger.com/atom/ns#' term='AP'/><category scheme='http://www.blogger.com/atom/ns#' term='Advanced Placement'/><category scheme='http://www.blogger.com/atom/ns#' term='test'/><title type='text'>Learn from the past AP Tests: 2000</title><content type='html'>&lt;p&gt;AP (Advanced Placement) tests are supposed to test your knowledge of a specific subject to see whether or not you should deserve college credit for you knowledge. For calculus and physics, there is a multiple choice and a free-response section. Needless to say, if you can pass the test, it is safe to say that you have a very good grasp of the subject.&lt;/p&gt;&lt;p&gt;For those of you familiar with the AP tests, you know that they are very strict about their tests. They generally have you sign a paper that says you will &lt;span style="font-style: italic;"&gt;never&lt;/span&gt; talk about the multiple choice questions and that you will not talk about the free-response questions till the questions have been published (which sometimes can take several years).&lt;/p&gt;&lt;p&gt;Fortunately, especially for those that will be taking an AP test in their future, some of the past free-response tests have been published for you to learn from. Now, without further adieu, here is the &lt;a href="http://www.collegeboard.com/ap/pdf/calc_ab_all.pdf"&gt;2000 AP Free-Response Questions for Calculus AB&lt;/a&gt;.&lt;/p&gt;&lt;p&gt;There are two parts of the test, each spanning 45 minutes. The first section &lt;span style="font-style: italic;"&gt;ONLY&lt;/span&gt; permits calculators. Of course, if you are looking at the test just for learning purposes, you do not need to follow such strict guidelines.&lt;/p&gt;&lt;p&gt;In future posts, I will take a look into some of the questions and try to help and perhaps give answers.&lt;br /&gt;&lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-6875198845507059149?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/6875198845507059149/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=6875198845507059149' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/6875198845507059149'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/6875198845507059149'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2007/01/learn-from-past-ap-tests-2000.html' title='Learn from the past AP Tests: 2000'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-1059551669712423694</id><published>2007-01-01T17:04:00.000-08:00</published><updated>2007-01-01T17:18:21.312-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='new year'/><category scheme='http://www.blogger.com/atom/ns#' term='game'/><title type='text'>Happy New Years</title><content type='html'>Happy New Years!&lt;br /&gt;&lt;br /&gt;Lets start the new year off with a bit of fun. Some of you may have heard this before.&lt;br /&gt;&lt;ol&gt;&lt;li&gt;Pick a number 2-9&lt;/li&gt;&lt;li&gt;Multiply your number by 9&lt;/li&gt;&lt;li&gt;Add the two resulting digits together (For example, if you chose the number 4, multiplying it by 9 would result in 36. Then add the numbers 3 and 6 together.)&lt;/li&gt;&lt;li&gt; Subtract 5 from your sum&lt;/li&gt;&lt;li&gt;Now find the corresponding letter. If after you subtract 5, you are left with the number 1, your letter is "A." If you are left with 2, your letter is "B." And so on.&lt;/li&gt;&lt;li&gt;Pick a country that starts with the letter you picked (ie. Argentina for A, Brazil for B)&lt;/li&gt;&lt;li&gt;Now, take the last letter in the country you chose, and pick an animal that starts with that letter. (Brazil ends in an "L," so you might choose lizard)&lt;/li&gt;&lt;li&gt;Now remember the country and animal.&lt;/li&gt;&lt;/ol&gt;Did you pick a Kangaroo from Denmark? :)&lt;br /&gt;&lt;br /&gt;I hope you have a great new year.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-1059551669712423694?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/1059551669712423694/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=1059551669712423694' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/1059551669712423694'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/1059551669712423694'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2007/01/happy-new-years.html' title='Happy New Years'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-853742974024144344</id><published>2006-12-17T20:57:00.000-08:00</published><updated>2006-12-17T21:01:18.093-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='Isaac Newton'/><category scheme='http://www.blogger.com/atom/ns#' term='calculus'/><category scheme='http://www.blogger.com/atom/ns#' term='physics'/><category scheme='http://www.blogger.com/atom/ns#' term='genius'/><title type='text'>Get to know Isaac Newton</title><content type='html'>If you are at all interested in calculus or physics, you need to get to know &lt;a href="http://en.wikipedia.org/wiki/Isaac_Newton"&gt;Isaac Newton&lt;/a&gt;. The man was a pure genius. He created calculus just so he could do physics! Brilliant!&lt;br /&gt;&lt;br /&gt;"Nature and nature's laws lay hid in night;&lt;br /&gt;God said "Let Newton be" and all was light."&lt;br /&gt;- Alexander Pope&lt;br /&gt;&lt;br /&gt;&lt;a href="http://en.wikipedia.org/wiki/Isaac_Newton"&gt;Isaac Newton Wikipedia&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-853742974024144344?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/853742974024144344/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=853742974024144344' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/853742974024144344'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/853742974024144344'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2006/12/get-to-know-isaac-newton.html' title='Get to know Isaac Newton'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-1134794439295751336</id><published>2006-12-12T21:08:00.000-08:00</published><updated>2006-12-12T21:15:08.112-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='derivative'/><category scheme='http://www.blogger.com/atom/ns#' term='calculus'/><category scheme='http://www.blogger.com/atom/ns#' term='calc101.com'/><category scheme='http://www.blogger.com/atom/ns#' term='integral'/><category scheme='http://www.blogger.com/atom/ns#' term='automatic'/><category scheme='http://www.blogger.com/atom/ns#' term='101'/><title type='text'>Calculus 101: the website</title><content type='html'>I stumbled opon a great website today (while I was studying for a calculus final, actually). It is called &lt;a href="http://www.calc101.com/" target="_new"&gt;Calc101.com&lt;/a&gt;.  It is a great resource for beginning calculus students. It will differentiate and itegrate most functions for you. The site also has "graphs, matrices, determinants,&lt;br /&gt;systems of linear equations, equations of lines" capabilities.&lt;br /&gt;&lt;br /&gt;The site has been added to my links.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-1134794439295751336?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/1134794439295751336/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=1134794439295751336' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/1134794439295751336'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/1134794439295751336'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2006/12/calculus-101-website.html' title='Calculus 101: the website'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-3456645307742175214.post-6682115461682033872</id><published>2006-12-08T10:24:00.000-08:00</published><updated>2006-12-08T10:32:00.537-08:00</updated><category scheme='http://www.blogger.com/atom/ns#' term='center'/><category scheme='http://www.blogger.com/atom/ns#' term='how to'/><category scheme='http://www.blogger.com/atom/ns#' term='gravity'/><category scheme='http://www.blogger.com/atom/ns#' term='wikiHow'/><category scheme='http://www.blogger.com/atom/ns#' term='physics'/><title type='text'>How to Calculate Center of Gravity</title><content type='html'>wikiHow, a website geared toward giving step by step instructions, had an article on calculating the center of gravity posted on December 6th. The article is easy to follow and, most importantly, it is accurate.&lt;br /&gt;&lt;br /&gt;&lt;a href="http://www.wikihow.com/Calculate-Center-of-Gravity"&gt;wikiHow: How To Calculate Center of Gravity&lt;/a&gt;&lt;br /&gt;&lt;br /&gt;You may know "center of gravity" as "center of mass." For the most part, these are the same thing.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/3456645307742175214-6682115461682033872?l=calculusphysics.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://calculusphysics.blogspot.com/feeds/6682115461682033872/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=3456645307742175214&amp;postID=6682115461682033872' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/6682115461682033872'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/3456645307742175214/posts/default/6682115461682033872'/><link rel='alternate' type='text/html' href='http://calculusphysics.blogspot.com/2006/12/how-to-calculate-center-of-gravity.html' title='How to Calculate Center of Gravity'/><author><name>Jason Pedersen</name><uri>http://www.blogger.com/profile/02257419790995719156</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>
